Forum Free news FREE blog Donate Search Subscribe jews/911 Feedback dna Gun poll RCC AIDS Home Fathers Surveys Holocaust IQ 14th Amdt 19th Amdt Israelites NWO Homicide Blacks Whites Signatory Talmud Watchman Gaelic Traitors Health? In article  "John Knight" writes: < < <"Jet" wrote in message     {...} <> <> <> What do you have to say about the fact you can't answer any of the <> questions you took girls to task for not being able to answer? <> <> Here's a really simple one: <> http://fathersmanifesto.net/timssh04.htm <> <> Brian got it wrong, he thought the objects started out at the same <> height and you don't have a clue. <> <> J < writes: < <"Cary Kittrell" wrote in message In article  "Parse Tree" writes: <> < <> <"Cary Kittrell" wrote in message <> <> In article  "John Knight" writes: <> <> <> <> <> <> <> <> <> The "resulting velocity would be the same" if both masses were <> <> the same acceleration the instant of release, but they were not.   The <> <> bottom mass was experiencing -2mg downards due to gravity and +2mg <> due to the tension in the spring.  The upper mass is experiencing a <> <> now unopposed -mg downwards due to gravity and a -2mg downwards due <> <> to the same spring tension.  You figure it out. <> < <> <> That is right as far is acceleration due to gravity is concerned, <> as is implied in my statement above.  But each body is experiencing <> additional forces due to the spring, so they will no be subject <> to the same accelerations.  If you mentally switch off gravity, <> the two bodies will move towards one another with an acceleration <> proportional to the 2mg tension in the spring.  If you now switch <> gravity back on, the whole system will accelerate downards at <> 1 g, but this acts equally on the whole system, so you're back <> to considering things in the frame of referrence of the system <> itself -- as Jet implied. < < <> <> Um, beg pardon?  Assuming the value of what unknown?  If you mean <> the spring tension, I simply said that the /initial/ spring <> tension is 2mg, because the lower mass is being pulled downwards <> by a force of 2mg due to gravity.  Since it isn't moving initially, <> there must be an equal and opposite force: 2mg of tension in the spring. < wrote in message news:ahkjf2\$rvp\$1@oasis.ccit.arizona.edu... > > In article  "Parse Tree" writes: > < > <"Cary Kittrell" wrote in message > <> In article  "Parse Tree" writes: > <> < > <> <"Cary Kittrell" wrote in message > <> <> <> In article  "John Knight" writes: > <> <> > <> <> <> <> <> <> <> <> <> > <> <> The "resulting velocity would be the same" if both masses were > <> <> <> the same acceleration the instant of release, but they were not. The > <> <> bottom mass was experiencing -2mg downards due to gravity and +2mg > <> <> due to the tension in the spring.  The upper mass is experiencing a > <> <> now unopposed -mg downwards due to gravity and a -2mg downwards due > <> <> to the same spring tension.  You figure it out. > <> < > <> <> <> > <> That is right as far is acceleration due to gravity is concerned, > <> as is implied in my statement above.  But each body is experiencing > <> additional forces due to the spring, so they will no be subject > <> to the same accelerations.  If you mentally switch off gravity, > <> the two bodies will move towards one another with an acceleration > <> proportional to the 2mg tension in the spring.  If you now switch > <> gravity back on, the whole system will accelerate downards at > <> 1 g, but this acts equally on the whole system, so you're back > <> to considering things in the frame of referrence of the system > <> itself -- as Jet implied. > < > < > > This suddenly grows more interesting.  I've been reading "spring"; it > in fact says "string". Yes, I noticed that.  But it's true even with a real spring. > < > > If you assume an infinitely strong string, then you are correct. Otherwise > they will indeed move, unless you've stretched the string inelastically. > However, I'm being picky, and you're on to the intention of the question, > I think. They will move, but they won't move the same amount that they are pulled on. Even a spring won't, unless it is perfectly elastic. > <> <> < > <> > <> Um, beg pardon?  Assuming the value of what unknown?  If you mean > <> the spring tension, I simply said that the /initial/ spring > <> tension is 2mg, because the lower mass is being pulled downwards > <> by a force of 2mg due to gravity.  Since it isn't moving initially, > <> there must be an equal and opposite force: 2mg of tension in the spring. > < > < > > Assuming an infinitely strong string -- one whose relaxation is zero -- then > you are correct. Yes.  There are too many assumptions in these questions though.  I can see why they're difficult.  There was another question about probability which didn't even seem to specify if the two values involved were independent or not.

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